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2x^2+60x-800=0
a = 2; b = 60; c = -800;
Δ = b2-4ac
Δ = 602-4·2·(-800)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10000}=100$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-100}{2*2}=\frac{-160}{4} =-40 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+100}{2*2}=\frac{40}{4} =10 $
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